document.write( "Question 1007343: A plane flies from Chicago to Los Angeles, A distance of 2000 miles, in 4 hours. It flies against a 50 mile per hour wind. The plane flies the return trip from Las Angles back to Chicago in 3 and 1/3 hours. Find the speed of the plane in still air. \n" ); document.write( "
Algebra.Com's Answer #623277 by lwsshak3(11628)\"\" \"About 
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A plane flies from Chicago to Los Angeles, A distance of 2000 miles, in 4 hours. It flies against a 50 mile per hour wind. The plane flies the return trip from Las Angles back to Chicago in 3 and 1/3 hours. Find the speed of the plane in still air.
\n" ); document.write( "3 1/3 hrs=10/3 hrs
\n" ); document.write( "let x=speed of plane in still air
\n" ); document.write( "x+50=speed of plane with the wind
\n" ); document.write( "x-50=speed of plane against the wind
\n" ); document.write( "travel time*speed=distance(same for both directions)
\n" ); document.write( "4(x-50)=10/3(x-50)
\n" ); document.write( "12(x-50)=10(x+50)
\n" ); document.write( "12x-600=10x+500
\n" ); document.write( "2x=1100
\n" ); document.write( "x=550
\n" ); document.write( "speed of plane in still air=550 mph
\n" ); document.write( "
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