document.write( "Question 1007222: If an object is projected vertically upward from an altitude of s0 feet with an initial velocity of v0 ft/sec, then its distance s(t) above the ground after t seconds is s(t) = −16t^2 + v0t + s0.\r
\n" ); document.write( "\n" ); document.write( "If s(2) = 131 and s(4) = 89, what are v0 and s0?\r
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Algebra.Com's Answer #623271 by ankor@dixie-net.com(22740)\"\" \"About 
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If an object is projected vertically upward from an altitude of s0 feet with an initial velocity of v0 ft/sec, then its distance s(t) above the ground after t seconds is s(t) = −16t^2 + v0t + s0.
\n" ); document.write( "If s(2) = 131 and s(4) = 89, what are v0 and s0?
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each pair of values
\n" ); document.write( "t=2; s=131
\n" ); document.write( "-16(2^2) + 2Vo + So = 131
\n" ); document.write( "-64 + 2Vo + So = 131
\n" ); document.write( "2Vo + So = 131 + 64
\n" ); document.write( "2Vo + So = 195
\n" ); document.write( "and
\n" ); document.write( "t=4; s=89
\n" ); document.write( "-16(4^2) + 4Vo + So = 89
\n" ); document.write( "-256 + 4Vo + So = 89
\n" ); document.write( "4Vo + So = 89 + 256
\n" ); document.write( "4Vo + So = 345
\n" ); document.write( ":
\n" ); document.write( "Use elimination on these two equations
\n" ); document.write( "4Vo + So = 345
\n" ); document.write( "2Vo + So = 195
\n" ); document.write( "-----------------Subtraction eliminated So, find Vo
\n" ); document.write( "2Vo = 150
\n" ); document.write( "Vo = 75 ft/sec is the upward velocity
\n" ); document.write( ":
\n" ); document.write( "Find So
\n" ); document.write( "2(75) + So = 195
\n" ); document.write( "150 + So = 195
\n" ); document.write( "So = 195- 150
\n" ); document.write( "So = 45 ft is the initial height above the ground
\n" ); document.write( ":
\n" ); document.write( "The equation
\n" ); document.write( "S(t) = -16t^2 + 75t + 45
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