document.write( "Question 1007222: If an object is projected vertically upward from an altitude of s0 feet with an initial velocity of v0 ft/sec, then its distance s(t) above the ground after t seconds is s(t) = −16t^2 + v0t + s0.\r
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document.write( "If s(2) = 131 and s(4) = 89, what are v0 and s0?\r
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Algebra.Com's Answer #623271 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! If an object is projected vertically upward from an altitude of s0 feet with an initial velocity of v0 ft/sec, then its distance s(t) above the ground after t seconds is s(t) = −16t^2 + v0t + s0. \n" ); document.write( "If s(2) = 131 and s(4) = 89, what are v0 and s0? \n" ); document.write( ": \n" ); document.write( "Write an equation for each pair of values \n" ); document.write( "t=2; s=131 \n" ); document.write( "-16(2^2) + 2Vo + So = 131 \n" ); document.write( "-64 + 2Vo + So = 131 \n" ); document.write( "2Vo + So = 131 + 64 \n" ); document.write( "2Vo + So = 195 \n" ); document.write( "and \n" ); document.write( "t=4; s=89 \n" ); document.write( "-16(4^2) + 4Vo + So = 89 \n" ); document.write( "-256 + 4Vo + So = 89 \n" ); document.write( "4Vo + So = 89 + 256 \n" ); document.write( "4Vo + So = 345 \n" ); document.write( ": \n" ); document.write( "Use elimination on these two equations \n" ); document.write( "4Vo + So = 345 \n" ); document.write( "2Vo + So = 195 \n" ); document.write( "-----------------Subtraction eliminated So, find Vo \n" ); document.write( "2Vo = 150 \n" ); document.write( "Vo = 75 ft/sec is the upward velocity \n" ); document.write( ": \n" ); document.write( "Find So \n" ); document.write( "2(75) + So = 195 \n" ); document.write( "150 + So = 195 \n" ); document.write( "So = 195- 150 \n" ); document.write( "So = 45 ft is the initial height above the ground \n" ); document.write( ": \n" ); document.write( "The equation \n" ); document.write( "S(t) = -16t^2 + 75t + 45 \n" ); document.write( " |