document.write( "Question 1007273: ln(x+2)+lnx=ln(x+12) \n" ); document.write( "

Algebra.Com's Answer #623222 by fractalier(6550) $\"\"$ $\"About$

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Using the laws of logarithms on
\n" ); document.write( "ln(x+2)+lnx=ln(x+12)
\n" ); document.write( "we get
\n" ); document.write( "ln x(x+2) = ln (x+12)
\n" ); document.write( "x(x+2) = x+12
\n" ); document.write( "x^2 + 2x = x + 12
\n" ); document.write( "x^2 + x - 12 = 0
\n" ); document.write( "(x + 4)(x - 3) = 0
\n" ); document.write( "x = -4 or x = 3
\n" ); document.write( "but x cannot be -4, so
\n" ); document.write( "x = 3 \n" ); document.write( "

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