document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1007245>Question 1007245</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I really need help with this. Afraid I'm not that great in Algebra. A chemist needs 170 millimeters of a 47% solution but has only 29% and 80% solutions available. Find how many milliliters of each that should be mixed to get the desired solution.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #623206 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=623206\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=ml of 29%<BR>\n" );
document.write( "170-x=ml of 80%<BR>\n" );
document.write( "the 170 ml is 47%<BR>\n" );
document.write( "0.29x+0.80(170-x)=170(.47)<BR>\n" );
document.write( "0.29x+136-0.80x=79.9<BR>\n" );
document.write( "-0.51x=-56.1<BR>\n" );
document.write( "x=110 ml<BR>\n" );
document.write( "170-x=60 ml<BR>\n" );
document.write( "110ml of 0.29=0.319<BR>\n" );
document.write( "60 ml of 0.80=0.48<BR>\n" );
document.write( "They add to 0.799 pure acid<BR>\n" );
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