document.write( "Question 1007206: Solve the following inequality using interval notation: \r
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document.write( "1/x+3 + 1/x >_ 0\r
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document.write( ">_ = greater than or equal to\r
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document.write( "PLEASE HELP \n" );
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Algebra.Com's Answer #623191 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x can't be 0 or -3 \n" ); document.write( "Multiply through by x(x+3) to clear fractions, and you get x+x+3>=0, 2x+3>=0 and x>=-3/2. \n" ); document.write( "critical values are <-3, between -3 and -3/2, between -3/2 and 0, and greater than 0. \n" ); document.write( "pick -4 \n" ); document.write( "-1+-1/4 is not greater than or equal to zero. \n" ); document.write( "pick -2 \n" ); document.write( "1-1/2 not greater than or equal to zero. That works. \n" ); document.write( "Pick -3/2 itself. 1/1.5-1/(-3/2)=2/3-2/3 =0. That works. \n" ); document.write( "Try -1 \n" ); document.write( "1/2 -1 is not greater than 0. \n" ); document.write( ">0, both are positive and it works. \n" ); document.write( "The inequality works \r \n" ); document.write( "\n" ); document.write( "(-3,-3/2]U[0,oo) \n" ); document.write( " \n" ); document.write( " |