document.write( "Question 1007208: A man rows a boat 910 feet upstream against a constant current in 14 minutes. He then rows 525 feet downstream (with the same current) in 7 minutes. Find the speed of the current and the equivalent rate at which he can row in still water. \n" ); document.write( "
Algebra.Com's Answer #623189 by addingup(3677)\"\" \"About 
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Let speed of rowing be x feet per minute AND speed of current be y feet per minute.
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\n" ); document.write( "Let's remember the formula we need to use, it's the one for distance modified:
\n" ); document.write( "Distance= Speed*time Since we want the speed of the current, divide both sides by time:
\n" ); document.write( "D/t= S*t/t On the right, t multiplying and t dividing cancel each other and we get:
\n" ); document.write( "D/t= S This is the formula we will use, which we derived from D= St
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\n" ); document.write( "UPSTREAM
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\n" ); document.write( "x - y ft/minute= Speed upstream
\n" ); document.write( "x - y = 910/14
\n" ); document.write( "x - y = 65 Add y on both sides:
\n" ); document.write( "x = 65+y
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\n" ); document.write( "DOWNSTREAM
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\n" ); document.write( "x + y = 525/7
\n" ); document.write( "x + y = 75 Now substitute for x, since we just said that x= 65+y:
\n" ); document.write( "65+y+y= 75
\n" ); document.write( "2y= 75 - 65
\n" ); document.write( "2y= 10 divide both sides by 2:
\n" ); document.write( "y= 5 The speed of the current is 5 feet per minute
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\n" ); document.write( "(A) + (B)= 65 + 75= 140\r
\n" ); document.write( "\n" ); document.write( "2x = 100\r
\n" ); document.write( "\n" ); document.write( "x = 50 ' / minute ANSWER\r
\n" ); document.write( "\n" ); document.write( "y = 5' / minute ANSWER
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