document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=86209>Question 86209</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x-4(2x-3) > 5-(4-7x) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #62317 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=62317\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x-4(2x-3) > 5-(4-7x) First we get rid of parens\r<BR>\n" );
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document.write( "3x-8x+12>5-4+7x  subtract 7x and also 12 from both sides\r<BR>\n" );
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document.write( "3x-8x+12-12-7x>5-4-12+7x-7x  collect like terms\r<BR>\n" );
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document.write( "-12x>-11  divide both sides by -12 (remember, inequality sign reverses)\r<BR>\n" );
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document.write( "x<11/12\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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