document.write( "Question 1007171: Solve the given problem related to population growth. \r
\n" ); document.write( "\n" ); document.write( "The number of bacteria
\n" ); document.write( "N(t)
\n" ); document.write( " present in a culture at time t hours is given by
\n" ); document.write( "N(t) = 2500(2)^t.
\n" ); document.write( "Find the number of bacteria when
\n" ); document.write( "t = 0 hours
\n" ); document.write( " and
\n" ); document.write( "t = 4 hours.
\n" ); document.write( "(a) t = 0 hours
\n" ); document.write( "
\n" ); document.write( " bacteria \r
\n" ); document.write( "\n" ); document.write( "(b) t = 4 hours
\n" ); document.write( "
\n" ); document.write( " bacteria
\n" ); document.write( "

Algebra.Com's Answer #623157 by fractalier(6550)\"\" \"About 
You can put this solution on YOUR website!
Given the growth equation
\n" ); document.write( "\"N%28t%29+=+2500%2A2%5Et\"
\n" ); document.write( "we merely plug in the various values for t and get
\n" ); document.write( "N(0) = 2500*2^0 = 2500 bacteria
\n" ); document.write( "N(4) = 2500*2^4 = 40000 bacteria
\n" ); document.write( "
\n" );