document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1007119>Question 1007119</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangular garden is 48 square feet. How much fencing will be needed to enclose if its length is 2 feet longer than its width? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #623130 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=623130\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In this problem we have<BR>\n" );
document.write( "A = LW = 48  and<BR>\n" );
document.write( "L = W + 2<BR>\n" );
document.write( "Now substitute this into the first equation and get<BR>\n" );
document.write( "(W + 2)(W) = 48<BR>\n" );
document.write( "W^2 + 2W - 48 = 0<BR>\n" );
document.write( "(W + 8)(W - 6) = 0<BR>\n" );
document.write( "so the width is 6 feet<BR>\n" );
document.write( "The length must then be 8 feet.<BR>\n" );
document.write( "The border fence must be the perimeter...<BR>\n" );
document.write( "P = 2L + 2W = 2(8) + 2(6) = 28 feet </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );