document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1007134>Question 1007134</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A Chemist has 35% NaCl solution and 50% NaCl solution. How many liters of each should he mix to get 10L of NaCl solution with 40% base concentration?\r<BR>\n" );
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document.write( "Please help with this word problem involving systems of linear equations.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #623127 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=623127\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the amount of 35% solution, x.<BR>\n" );
document.write( "Then the amount of 50% solution would be 10-x.<BR>\n" );
document.write( "The set up looks like this:<BR>\n" );
document.write( ".35x + .50(10-x) = .40(10)<BR>\n" );
document.write( "Now work it out...<BR>\n" );
document.write( ".35x + 5 - .50x = 4<BR>\n" );
document.write( "-.15x = -1<BR>\n" );
document.write( "x = 6.67 L of 35% and then<BR>\n" );
document.write( "10-x = 3.33 L of 50% solution </SPAN>\n" );
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