document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1007141>Question 1007141</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Q9. Solve for pH: pH = -log10[H^+] Find the pH if the [H^+] = 9.6 x 10-6.\r<BR>\n" );
document.write( "\n" );
document.write( "    a. 6.02<BR>\n" );
document.write( "    b. 5.02<BR>\n" );
document.write( "    c. 6.98<BR>\n" );
document.write( "    d. 5.98<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #623125 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=623125\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For an H+ concentration of 9.6 x 10^-6, we take the log of it and then multiply that by -1...<BR>\n" );
document.write( "pH = -log10[H^+] = -log10(9.6 x 10^-6) = 5.018 or<BR>\n" );
document.write( "Choice B. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );