document.write( "Question 1007123: Please help!
\n" ); document.write( "If x,y,z are integers greater than 1 and if xy =24 and yz=56,which of the following must be true? and how?
\n" ); document.write( "A) x\n" ); document.write( "B) y\n" ); document.write( "C) z\n" ); document.write( "D) y\n" ); document.write( "

Algebra.Com's Answer #623115 by Theo(13342)\"\" \"About 
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xy = 24 yields y = 24/x
\n" ); document.write( "yz = 56 yields y = 56/z\r
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\n" ); document.write( "\n" ); document.write( "y equal to both yields 24/x = 56/z
\n" ); document.write( "that leads to 24z = 56x
\n" ); document.write( "that leads to z = 56x/24\r
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\n" ); document.write( "\n" ); document.write( "that means that z has to be greater than x and the ratio of z to x has to be 56/24.\r
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\n" ); document.write( "\n" ); document.write( "since 56/24 is not an integer, then x has to be a multiple of whatever makes 56/24 * x an integer.\r
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\n" ); document.write( "\n" ); document.write( "56/24 reduces to 7/3.\r
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\n" ); document.write( "\n" ); document.write( "x can be equal to 3,6,9,12,15,18,.....\r
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\n" ); document.write( "\n" ); document.write( "in other words x can be a multiple of 3.\r
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\n" ); document.write( "\n" ); document.write( "but not all multiples of 3 will work.\r
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\n" ); document.write( "\n" ); document.write( "that's because xy has to be equal to 24.\r
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\n" ); document.write( "\n" ); document.write( "when x = 3, y is equal to 8.
\n" ); document.write( "when x = 6, y is equal to 4.
\n" ); document.write( "when x = 9, y is not an integer.
\n" ); document.write( "when x = 12, y is equal to 2.
\n" ); document.write( "when x = 15, y is not an integer.
\n" ); document.write( "when x = 18, y is not an integer.
\n" ); document.write( "hen x = 21, y is not an integer.
\n" ); document.write( "when x = 24, y is equal to 1 which is not greater than 1.\r
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\n" ); document.write( "\n" ); document.write( "the only possible values of x are 3 or 6 or 12.\r
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\n" ); document.write( "\n" ); document.write( "when x is 3, y is 8, and z is 7 because xy = 24 and yz = 56.
\n" ); document.write( "you get x < z < y
\n" ); document.write( "that is not one of the selections.\r
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\n" ); document.write( "\n" ); document.write( "when x is 6, y is 4 and z is 14 because 6*4 = 24 and 4*14 = 56.
\n" ); document.write( "you get y < x < z
\n" ); document.write( "that is selection B.\r
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\n" ); document.write( "\n" ); document.write( "when x is 12, y is 2 and z is 28 because 12*2 = 24 and 2*28 = 56.
\n" ); document.write( "you get y < x < z
\n" ); document.write( "this is selection B.\r
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\n" ); document.write( "\n" ); document.write( "i would go with selection B.
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