document.write( "Question 1007120: The 3rd and 6th terms of a gp are 108 and _32 respectively find the common ratio and the first term \n" ); document.write( "
Algebra.Com's Answer #623107 by Edwin McCravy(20056)\"\" \"About 
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document.write( "The gp is:\r\n" );
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document.write( "______, _____, 108, ____, _____,    32, _____, _____, ...\r\n" );
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document.write( "which is actually this sequence:\r\n" );
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document.write( "108/r², 108/r, 108, 108r, 108r², 108r³, 108d4, 108d5, ...\r\n" );
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document.write( "So the 6th term, 32, must equal 108r³\r\n" );
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document.write( "                    32 = 108r³\r\n" );
document.write( "                32/108 = r³\r\n" );
document.write( "                  8/27 = r³\r\n" );
document.write( "                 2³/3³ = r³\r\n" );
document.write( "                (2/3)³ = r³\r\n" );
document.write( "                   2/3 = r\r\n" );
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document.write( "The first term is 108/r² = 108/(2/3)² = 108/(4/9) = 108(9/4) = 243\r\n" );
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document.write( "Checking the sequence, we use first term 243 and common ratio 2/3\r\n" );
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document.write( "243, 162, 108, 72, 48, 32, ...\r\n" );
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document.write( "The third term is 108 and the 6th term is 32.\r\n" );
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document.write( "Edwin

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