document.write( "Question 1007037: Solve each polynomial equation by factoring. \r
\n" ); document.write( "\n" ); document.write( "1. 5x^3+10x^2+5x=0. \r
\n" ); document.write( "\n" ); document.write( "For #1 - Would this answer be cannot be factored ? Because I did it, and i'm getting x = {0, -1, -1}.\r
\n" ); document.write( "\n" ); document.write( "2. x^3+2x^2-9x-18=0\r
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Algebra.Com's Answer #623066 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
Solve each polynomial equation by factoring. \r\n" );
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document.write( "1. \r\n" );
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document.write( "5x³+10x²+5x = 0\r\n" );
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document.write( "Factor out 5x\r\n" );
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document.write( "5x(x²+2x+1) = 0\r\n" );
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document.write( "Factor the quadratic in the parentheses:\r\n" );
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document.write( "5x(x+1)(x+1) = 0\r\n" );
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document.write( "5x=0; x+1=0;  x+1=0\r\n" );
document.write( " x=0;   x=-1    x=-1    \r\n" );
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\n" ); document.write( "For #1 - Would this answer be cannot be factored ?
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document.write( "No, for we factored it twice.\r\n" );
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\n" ); document.write( "Because I did it, and i'm getting x = {0, -1, -1}.
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document.write( "That's the correct solution but the only way to get it\r\n" );
document.write( "is to factor the polynomial.  \r\n" );
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document.write( "2. \r\n" );
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document.write( "x³+2x²-9x-18 = 0\r\n" );
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document.write( "Factor x² out of the first two terms on the left \r\n" );
document.write( "and factor -9 out of the last two terms on the left:\r\n" );
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document.write( "x²(x+2)-9(x+2) = 0\r\n" );
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document.write( "We factor out the common factor (x+2)\r\n" );
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document.write( "(x+2)(x²-9) = 0\r\n" );
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document.write( "Factor the expression in the second parentheses as\r\n" );
document.write( "the difference of two squares:\r\n" );
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document.write( "(x+2)(x-3)(x+3) = 0\r\n" );
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document.write( "Use the zero-factor property:\r\n" );
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document.write( "x+2=0;  x-3=0;  x+3=0\r\n" );
document.write( "  x=-2;   x=3;    x=-3\r\n" );
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document.write( "Edwin

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