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document.write( "Let x represent the smallest integer in any case of consecutive\r\n" );
document.write( "integers with sum 2015.\r\n" );
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document.write( "The sum of n consecutive positive integers beginning with x, \r\n" );
document.write( "using the sum formula for an arithmetic sequence \r\n" );
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document.write( "with a1=x and d=1\r\n" );
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document.write( "Setting that equal to 2015\r\n" );
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\r\n" );
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document.write( "Multiplying both sides by 2 to clear the fraction\r\n" );
document.write( "and simplifying:\r\n" );
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document.write( "

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document.write( "

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document.write( "

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document.write( "

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document.write( "
, the smallest integer.\r\n" );
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document.write( "From 

,\r\n" );
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document.write( "we see that n, the number of terms, and 2x+n-1 make up a factor \r\n" );
document.write( "pair of 4030. \r\n" );
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document.write( "We can factor 4030 into a pair of factors the following 8 ways:\r\n" );
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document.write( "n×(2x+n-1) = 4030, x = (4030+n-n^2)/(2n) = smallest integer\r\n" );
document.write( "----------------------------------------\r\n" );
document.write( "1×4030 x = 2015 <--ignore since only 1 integer, we need 2 or more \r\n" );
document.write( "2×2015 x = 1007 \r\n" );
document.write( "5×806 x = 401\r\n" );
document.write( "10×403 x = 197\r\n" );
document.write( "13×310 x = 149\r\n" );
document.write( "26×155 x = 65\r\n" );
document.write( "31×130 x = 50 \r\n" );
document.write( "62×65 x = 2\r\n" );
document.write( "---------------------------\r\n" );
document.write( " total = 1871 \r\n" );
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document.write( "The total of the smallest integers x is 1871\r\n" );
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document.write( "Answer: 1841\r\n" );
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document.write( "Edwin
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