document.write( "Question 1006911: How to take the domain of:\r
\n" ); document.write( "\n" ); document.write( "sqrt(x-1)-ln(15-x)\r
\n" ); document.write( "\n" ); document.write( "Please show how to solve
\n" ); document.write( "Thank you \n" ); document.write( "

Algebra.Com's Answer #623000 by MathTherapy(10552) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( "How to take the domain of:\r
\n" ); document.write( "\n" ); document.write( "sqrt(x-1)-ln(15-x)\r
\n" ); document.write( "\n" ); document.write( "Please show how to solve
\n" ); document.write( "Thank you
\n" ); document.write( "

Set each expression > 0, since the domain MUST be POSITIVE
\n" );
document.write( "We then get: x - 1 > 0______x > 1
\n" );
document.write( "Also, 15 - x > 0
\n" );
document.write( "- x > - 15
\n" );
document.write( " ---- Inequality sign changes when dividing by a negative number (< 0)
\n" );
document.write( "x < 15 
\n" );
document.write( "Therefore, domain, or  \n" );
document.write( "

\n" );