document.write( "Question 1006967: This problem is really confusing me. I've been trying for a while but just don't know how to do it. Could you help?\r
\n" ); document.write( "\n" ); document.write( "A factory has an order for 23,500 paper clips. Machine A can make 1500 paper clips per hour while Machine B can make 2500 paper clips per hour. Machine A starts at 8:00 A.M. and Machine B starts at 1:00 P.M. At what time will the two machines complete the job?
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Algebra.Com's Answer #622999 by josmiceli(19441)\"\" \"About 
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it sounds like there is 5 hrs ( 8 AM to 1 PM )
\n" ); document.write( "when only machine A is making paper clips
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\n" ); document.write( "\"+1500+\" paper clips /hr is A's rate of making them
\n" ); document.write( "\"+2500+\" paper cips / hr is B's rate of making them
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\n" ); document.write( "What part of the order does machine A get done
\n" ); document.write( "in 5 hrs working alone?
\n" ); document.write( "\"+1500%2A5+=+7500+\" paper clips
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\n" ); document.write( "That leaves \"+23500+-+7500+=+16000+\"
\n" ); document.write( "left to be made
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\n" ); document.write( "Let \"+t+\" = the number of hrs past 1PM when both
\n" ); document.write( "machines working together will finish the order
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\n" ); document.write( "Add their rates of working to get their rate working together
\n" ); document.write( "Their rate working together is:
\n" ); document.write( "[ 16000 paper clips ] / [ t hrs ]
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\n" ); document.write( "\"+1500+%2B+2500+=+16000%2Ft+\"
\n" ); document.write( "( note that I am adding rates to get a rate )
\n" ); document.write( "\"+4000t+=+16000+\"
\n" ); document.write( "\"+t+=+4+\" hrs
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\n" ); document.write( "1 PM + 4 hrs = 5 PM when the order will be finished
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