document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1006939>Question 1006939</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 3 more than 4 times another. If the sum of the two numbers is 43, find the two number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #622986 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=622986\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the numbers x and y.  Then we have<BR>\n" );
document.write( "x = 4y + 3 and<BR>\n" );
document.write( "x + y = 43<BR>\n" );
document.write( "Substitute the first into the second equations and get<BR>\n" );
document.write( "4y + 3 + y = 43<BR>\n" );
document.write( "5y + 3 = 43<BR>\n" );
document.write( "5y = 40<BR>\n" );
document.write( "y = 8<BR>\n" );
document.write( "x is then 35. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );