document.write( "Question 1006928: 4x+2 greater than or equal to 14
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Algebra.Com's Answer #622959 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! 4x + 2 >= 14 \n" ); document.write( "Now subtract 2 from both sides, then divide by four and get \n" ); document.write( "4x >= 12 \n" ); document.write( "x >= 3 \n" ); document.write( "x is greater than or equal to 3. \n" ); document.write( " |