document.write( "Question 1006751: The length of a rectangle is 3m less than twice the width, and the area of the rectangle is 27 m2. Find the dimensions of the rectangle. \r
\n" ); document.write( "\n" ); document.write( "Length
\n" ); document.write( "Width
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Algebra.Com's Answer #622924 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Hi there,
\n" ); document.write( "Make width = 'x'
\n" ); document.write( "Length = 2x - 3
\n" ); document.write( "Area = Length x Width
\n" ); document.write( "27 = (2x - 3) x (x)
\n" ); document.write( "27 = 2x^2 - 3x
\n" ); document.write( "2x^2 - 3x - 27 = 0
\n" ); document.write( "Factorise:
\n" ); document.write( "(2x - 9)(x + 3)= 0
\n" ); document.write( "x + 3 = 0
\n" ); document.write( "x = -3 Disregard as -ve
\n" ); document.write( "2x - 9 = 0
\n" ); document.write( "2x = 9
\n" ); document.write( "x = 4.5
\n" ); document.write( "Width = 4.5m
\n" ); document.write( "Length = 6m
\n" ); document.write( "Hope this helps :-)
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