document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=86153>Question 86153</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x - 5(3x - 7) = 2(x + 9) + 45 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #62287 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=62287\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x-5(3x-7)=2(x+9)+45 First, lets get rid of parens\r<BR>\n" );
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document.write( "3x-15x+35=2x+18+45  Next, we will subtract 35 and also 2x from both sides. This will get the unknowns on one side of the equation and the numbers on the other\r<BR>\n" );
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document.write( "3x-15x+35-35-2x=2x-2x+18+45-35  now we will collect like terms \r<BR>\n" );
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document.write( "-14x=28  divide both sides by -14\r<BR>\n" );
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document.write( "x=-2-------------------------------ans\r<BR>\n" );
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document.write( "CK\r<BR>\n" );
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document.write( "3(-2)-5{3(-2)-7}=2(-2+9)+45\r<BR>\n" );
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document.write( "-6-5(-6-7)=2(7)+45\r<BR>\n" );
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document.write( "-6-5(-13)=14+45<BR>\n" );
document.write( "-6+65=14+45<BR>\n" );
document.write( "59=59\r<BR>\n" );
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document.write( "Hope this helps----ptaylor\r<BR>\n" );
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