document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1006799>Question 1006799</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you solve for theta if cos0= negative square root of 2 by 2. Also, i am limited to the third and fourth quadrant. I figured the answer had to be either 7pi by 6 or 5 pi by 4. My book said 5 pi by 4 but how would I know which special triangle to use?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #622854 by </B><A HREF=/tutors/aboutme.mpl?userid=HaundC><B>HaundC(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=HaundC><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=622854\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For that case, theta WOULD be 5pi/4.\r<BR>\n" );
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document.write( "For 30 degree triangles (pi/6, 5pi/6, 7pi/6, 11pi/6), your sine will always be +/-(sqrt(3))/2, your cos will always be +/-1/2, and your tan will always be +/-(sqrt(3))/3. \r<BR>\n" );
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document.write( "For a 45 degree triangle (pi/4, 3pi/4, 5pi/4, 7pi/4), your sin and cos will always be +/-(sqrt(2))/2, and your tan will always be +/-1.\r<BR>\n" );
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document.write( "For a 60 degree triangle (pi/3, 2pi/3, 4pi/3, 5pi/3), your sin will always be +/-(sqrt(3)/2, your cos will always be +/-1/2, and your tan will always be (sqrt(3)). \r<BR>\n" );
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document.write( "(whether they are positive or negative depend on what quadrant they are in)\r<BR>\n" );
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document.write( "It's a matter of just memorizing. </SPAN>\n" );
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