document.write( "Question 1006688: two cars left daisy's diner at the same time and traveled in opposite directions. one car traveled for 78 minutes. the other car traveled for 144 minutes at a rate of 5 km/h faster than the first car. if the faster car went twice as far as the slower car, how fast did each car travel? \n" ); document.write( "

Algebra.Com's Answer #622832 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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two cars left daisy's diner at the same time and traveled in opposite directions.
\n" ); document.write( " one car traveled for 78 minutes.
\n" ); document.write( " the other car traveled for 144 minutes at a rate of 5 km/h faster than the first car.
\n" ); document.write( " if the faster car went twice as far as the slower car, how fast did each car travel?
\n" ); document.write( "L
\n" ); document.write( "let s = speed of the 1st car
\n" ); document.write( "then
\n" ); document.write( "(s+5) = the speed of the 2nd car
\n" ); document.write( ":
\n" ); document.write( "Since we are using km per hr, we have convert the minutes to hrs
\n" ); document.write( "dist = time * speed
\n" ); document.write( "2nd car dist = twice 1st car dist
\n" ); document.write( " $\"144%2F60\"$ *(s+5) = 2( $\"78%2F60\"$ * s)
\n" ); document.write( "multiply both sides by 60
\n" ); document.write( "144(s+5) = 2(78s)
\n" ); document.write( "144s + 720 = 156s
\n" ); document.write( "720 = 156s - 144s
\n" ); document.write( "720 = 12s
\n" ); document.write( "s = 720/12
\n" ); document.write( "s = 60 km/hr speed of the 1st car
\n" ); document.write( "then obviously,
\n" ); document.write( "65 km/hr is the speed of the 2nd car
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this by finding the actual distance each traveled
\n" ); document.write( " $\"144%2F60\"$ * 65 = 156 km
\n" ); document.write( " $\"78%2F60\"$ * 60 = 78 km, half as far
\n" ); document.write( " \n" ); document.write( "

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