document.write( "Question 1006674: How much water must be added to 200 liters of mixture which is 80 percent alcohol to reduce it to a 75 percent mixture ? \n" ); document.write( "
Algebra.Com's Answer #622809 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! How much water must be added to 200 liters of mixture which is 80 percent alcohol to reduce it to a 75 percent mixture ? \n" ); document.write( ": \n" ); document.write( "Amt of alcohol remains the same, therefore a simple equation \n" ); document.write( "let w = amt of water to be added \n" ); document.write( ".80(200) = .75(w+200) \n" ); document.write( "160 = .75w + 150 \n" ); document.write( "160 - 150 = .75w \n" ); document.write( "10 = .75w \n" ); document.write( "w = 10/.75 \n" ); document.write( "w = 13 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this on your calc \n" ); document.write( ".8(200) = .75(213.33) \n" ); document.write( " \n" ); document.write( " |