document.write( "Question 1006700: The amount of Jen’s monthly phone bill is normally distributed with a mean of $60 and a standard deviation of $12. \r
\n" ); document.write( "\n" ); document.write( "68% of her phone bills are between $60-12 = 48 and $60+12 = 72
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Algebra.Com's Answer #622788 by stanbon(75887)\"\" \"About 
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The amount of Jen’s monthly phone bill is normally distributed with a mean of $60 and a standard deviation of $12. \r
\n" ); document.write( "\n" ); document.write( "68% of her phone bills are between $60-12 = 48 and $60+12 = 72
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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