document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1006659>Question 1006659</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The local middle school had a concert to raise money. Tickets were $6.00 for adults and $4.00 for children. The committee figured there were 480 in attendance and that $2340.00 was raised. How many adults and how many children attended? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #622773 by </B><A HREF=/tutors/aboutme.mpl?userid=Ani_g><B>Ani_g(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Ani_g><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=622773\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the number of adults = x & the number of children = y\r<BR>\n" );
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document.write( "Then, x+y=480....(1)\r<BR>\n" );
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document.write( "& 6x+4y=2340....(2)\r<BR>\n" );
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document.write( "Now, by eq(1)x 4 => 4x+4y=1920....(3)\r<BR>\n" );
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document.write( "Next, by eq(2)-eq(3), we get, 2x=420 or x=210\r<BR>\n" );
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document.write( "Therefore, y=480-210=270. <BR>\n" );
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