document.write( "Question 86140This question is from textbook
\n" ); document.write( ": Write an equation of a line that is perpendicular to y = 2x + 3 and
\n" ); document.write( " passes through (3,4).
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Algebra.Com's Answer #62274 by checkley75(3666)\"\" \"About 
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A LINE PERPENDICULAR TO THIS LINE [Y=2X+3] (red line)HAS A SLOPE (m) OF -1/2.
\n" ); document.write( "SEEING AS IT PASSES THROUGH (3,4) WE NEED TO SUBSTITUTE THESE VALUES FOR THE X & Y VALUES IN THE LINE EQUATION [Y=mX+b], ALONG WITH THE SLOPE (m=-1/2) & SOLVE FOR THE Y INTERCEPT (b).
\n" ); document.write( "4=-1/2*3+b
\n" ); document.write( "4=-3/2+b
\n" ); document.write( "b=4+3/2
\n" ); document.write( "b=4+1.5
\n" ); document.write( "b=5.5 THE Y INTERCEPT.
\n" ); document.write( "THUS WE HAVE THE LINE EQUATION:
\n" ); document.write( "Y=-X/2+5.5 (green line)
\n" ); document.write( "PROOF IN GRAPH FORM FOLLOWS:
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+y+=+2x+%2B3%2C+y+=+-x%2F2+%2B5.5%29+\" (graph 300x300 pixels, x from -10 to 10, y from -10 to 10, of TWO functions y = 2x +3 and y = -x/2 +5.5). \r
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