document.write( "Question 1006618: An object is moving in a straight line. The distance (in meters) from a fixed point is given by s= -2t^3 - 4t^2 + 6t + 4 where t≥0. Determine the acceleration when the velocity is -2m/s \n" ); document.write( "

Algebra.Com's Answer #622738 by ikleyn(52776) $\"\"$ $\"About$

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document.write( "The procedure is as follows:\r\n" );
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document.write( "1. Take the derivative of s by t.\r\n" );
document.write( "   You will get a quadratic polynomial of t for the velocity, v(t) = .\r\n" );
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document.write( "2. Solve the quadratic equation v(t) = -2 to find the time moment when the velocity is - 2 .\r\n" );
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document.write( "3. Take the second derivative of s by t to get the expression for the acceleration a(t).\r\n" );
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document.write( "4. Substitute the found value of t into the expression for acceleration to determine the unknown acceleration.\r\n" );
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document.write( "Good luck!\r\n" );
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