document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1006587>Question 1006587</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the area of a circle inscribed in a square of side 28cm <BR>\n" );
document.write( "Hint:diameter of the circle is equal to the side of the square <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #622706 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=622706\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The side of the square is s<BR>\n" );
document.write( "The area is s^2, which here is 28^2 or 784 cm^2.<BR>\n" );
document.write( "The area of the circle is pi*r^2, where r=14 cm<BR>\n" );
document.write( "That is 196*pi cm^2= 615.75 cm^2<BR>\n" );
document.write( "This is pi/4, which is the general form.<BR>\n" );
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