document.write( "Question 1006584: Jim can row his boat upstream at four kilometers per hour, and downstream at six kilometers per hour. He rowed upstream a certain distance and then rowed back downstream to his starting point in one hour. How far did he row upstream? \n" ); document.write( "
Algebra.Com's Answer #622704 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Row=4 km/h \n" ); document.write( "Current=C \n" ); document.write( "R-C=4 km/h \n" ); document.write( "R+C=6 km/h \n" ); document.write( "2R=10 \n" ); document.write( "R=5 km/h \n" ); document.write( "C=1 km/h \n" ); document.write( "t=time upstream in hr. \n" ); document.write( "1-t=time downstream in hr. \n" ); document.write( "4t=6(1-t) \n" ); document.write( "4t=6-6t \n" ); document.write( "10t=6 \n" ); document.write( "t=(3/5) hour or 12/5 km. upstream \n" ); document.write( "1-t=(2/5) hour or 12/5 km downstream \n" ); document.write( "12/5 km or 2.4 km. \n" ); document.write( " |