document.write( "Question 1006529: (1+2+3+...+19)20
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document.write( "(21+22+23+...+39)40\r
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document.write( "Find 3 (n)s\r
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Algebra.Com's Answer #622672 by ikleyn(52787)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "What to find ?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------------------------------------- \n" ); document.write( "Comment from student: simplify it into an expression using n \n" ); document.write( "-------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "OK. (Why do not write it from the very beginning?)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The sum in the numerator is the sum of first 19 terms of an arithmetic progression 1, 2, 3, . . . , 19\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "S = 1 + 2 + 3 + . . . + 19 = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The sum in the numerator is the sum of first 19 terms of an arithmetic progression 21, 22, 23, . . . , 39\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "T = 21 + 22 + 23 + . . . + 39 = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, the ratio you are asking for, is\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |