document.write( "Question 1006529: (1+2+3+...+19)20
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\n" ); document.write( "(21+22+23+...+39)40\r
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\n" ); document.write( "\n" ); document.write( "Find 3 (n)s\r
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Algebra.Com's Answer #622672 by ikleyn(52787)\"\" \"About 
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\n" ); document.write( "Comment from student: simplify it into an expression using n
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\n" ); document.write( "\n" ); document.write( "OK. (Why do not write it from the very beginning?)\r
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\n" ); document.write( "\n" ); document.write( "The sum in the numerator is the sum of first 19 terms of an arithmetic progression 1, 2, 3, . . . , 19\r
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\n" ); document.write( "\n" ); document.write( "S = 1 + 2 + 3 + . . . + 19 = \"%281+%2B+19%29%2F2%2A19\" = \"20%2F2%2A19\" = 10*19.\r
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\n" ); document.write( "\n" ); document.write( "The sum in the numerator is the sum of first 19 terms of an arithmetic progression 21, 22, 23, . . . , 39\r
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\n" ); document.write( "\n" ); document.write( "T = 21 + 22 + 23 + . . . + 39 = \"%2821+%2B+39%29%2F2%2A19\" = \"60%2F2%2A19\" = 30*19.\r
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\n" ); document.write( "\n" ); document.write( "Hence, the ratio you are asking for, is\r
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\n" ); document.write( "\n" ); document.write( "\"%28S%2A20%29%2F%28R%2A40%29\" = \"%2810%2A19%29%2F%2830%2A19%2A2%29\" = \"10%2F%2830%2A2%29\" = \"1%2F6\".\r
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