document.write( "Question 1006540: Solve the unknown value in the following equation\r
\n" ); document.write( "\n" ); document.write( "log(base 9)9 ^ log(base 3)3 \n" ); document.write( "

Algebra.Com's Answer #622649 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+log%28+9%2C+%289%5E%28+log%28+3%2C+3+%29%29+%29%29+\"$
\n" ); document.write( "Is this it? If so,
\n" ); document.write( "First find $\"+log%28+3%2C+3+%29+\"$
\n" ); document.write( "If I say:
\n" ); document.write( " $\"+x+=+log%28+3%2C+3+%29+\"$ , then the inverse of this is:
\n" ); document.write( " $\"+3%5Ex+=+3+\"$
\n" ); document.write( " $\"+x+=+1+\"$
\n" ); document.write( " $\"+log%28+3%2C+3+%29+=+1+\"$
\n" ); document.write( "------------
\n" ); document.write( "Now I have:
\n" ); document.write( " $\"+log%28+9%2C+9+%29+\"$
\n" ); document.write( " $\"+x+=+log%28+9+%2C+9+%29+\"$
\n" ); document.write( " $\"+9%5Ex+=+9+\"$
\n" ); document.write( " $\"+x+=+1+\"$
\n" ); document.write( " $\"+log%28+9%2C+9+%29+=+1+\"$
\n" ); document.write( "----------------
\n" ); document.write( "The original expression = 1 \n" ); document.write( "

\n" );