document.write( "Question 1006514: Let ln (a)=2, ln (b)=3, ln (c)=5. Solve:
\n" ); document.write( "f (x)=(ln (c^2))(ln (a^4/b^2))^-1
\n" ); document.write( "

Algebra.Com's Answer #622648 by MathTherapy(10552)\"\" \"About 
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Let ln (a)=2, ln (b)=3, ln (c)=5. Solve:
\n" ); document.write( "f (x)=(ln (c^2))(ln (a^4/b^2))^-1
\n" ); document.write( "
ln a = 2
\n" ); document.write( "ln b = 3
\n" ); document.write( "ln c = 5
\n" ); document.write( "\"f%28x%29+=+%28ln+%28c%5E2%29%29%28ln+%28a%5E4%2Fb%5E2%29%29%5E%28-+1%29\"
\n" ); document.write( "\"ln+%28c%5E2%29+=+2+ln+%28c%29\" ------- Applying \"ln+%28p%5Eq%29+=+q+ln+%28p%29\"
\n" ); document.write( "\"%28ln+%28a%5E4%2Fb%5E2%29%29%5E%28-+1%29+=+1%2F%28ln+%28a%5E4%2Fb%5E2%29%29\"
\n" ); document.write( "We therefore have:
\n" ); document.write( "\"f%28x%29+=+2+ln+%28c%29+%2A+%281%2F%28ln+%28a%5E4%2Fb%5E2%29%29%29\"
\n" ); document.write( "\"f%28x%29+=+2+ln+%28c%29+%2A+%281%2F%28ln+%28a%5E4%29+-+ln+%28b%5E2%29%29%29\" --- Applying \"ln+%28p%2Fq%29\" = ln p – ln q
\n" ); document.write( "\"f%28x%29+=+2+ln+%28c%29+%2A+%281%2F%284+ln+%28a%29+-+2+ln+%28b%29%29%29\" ---- Applying \"ln+%28p%5Eq%29\" = q ln p
\n" ); document.write( "\"f%28x%29+=+2%285%29+%2A+%281%2F%284%282%29+-+2%283%29%29%29\" ----------- Substituting 5 for ln c, 2 for ln a, and 3 for ln b
\n" ); document.write( "\"f%28x%29+=+10+%2A+%281%2F%288+-+6%29%29\"
\n" ); document.write( "\"f%28x%29+=+10+%2A+%281%2F2%29\", or \"highlight_green%285%29\" \n" ); document.write( "
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