document.write( "Question 86176: Can you please help with this equation?
\n" ); document.write( "Find the roots of 3x^2+2x-4=0.
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Algebra.Com's Answer #62263 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "the general form of the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"3%2Ax%5E2%2B2%2Ax-4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+%282%29%5E2-4%2A3%2A-4+%29%29%2F%282%2A3%29\" Plug in a=3, b=2, and c=-4\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+4-4%2A3%2A-4+%29%29%2F%282%2A3%29\" Square 2 to get 4\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+4%2B48+%29%29%2F%282%2A3%29\" Multiply \"-4%2A-4%2A3\" to get \"48\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+52+%29%29%2F%282%2A3%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+2%2Asqrt%2813%29%29%2F%282%2A3%29\" Simplify the square root\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+2%2Asqrt%2813%29%29%2F6\" Multiply 2 and 3 to get 6\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B+2%2Asqrt%2813%29%29%2F6\" or \"x+=+%28-2+-+2%2Asqrt%2813%29%29%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=0.86851709182133\" or \"x=-1.535183758488\"\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"x=0.86851709182133\" or \"x=-1.535183758488\"\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph \"3%2Ax%5E2%2B2%2Ax-4\" we get:\r
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\n" ); document.write( "\n" ); document.write( "when we use the root finder feature on our calculator, we find that \"x=0.86851709182133\" and \"x=-1.535183758488\".So this verifies our answer
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