document.write( "Question 1006496: I have 40 questions, 4 marks given for a correct answer, 2 marks deducted for each wrong answer and 1 mark deducted for for each answer not attempted I attempt 19 and score 25 marks.how many questions did I get right? \n" ); document.write( "
Algebra.Com's Answer #622628 by Ani_g(8)\"\" \"About 
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Let the number of correct answers = x & number of incorrect answers = y\r
\n" ); document.write( "\n" ); document.write( "Since I attempted 19 questions, then x + y = 19 ......(1)\r
\n" ); document.write( "\n" ); document.write( "For x no. of correct answers I get = 4x\r
\n" ); document.write( "\n" ); document.write( "Deduction for y no. of incorrect answers = - 2y\r
\n" ); document.write( "\n" ); document.write( "Deduction for (40-19) = 21 non-attempted questions = - 21\r
\n" ); document.write( "\n" ); document.write( "Adding these three we get my score, i.e., 25.\r
\n" ); document.write( "\n" ); document.write( "Hence, 4x - 2y - 21 = 25\r
\n" ); document.write( "\n" ); document.write( " Or, 4x - 2y = 25 +21 = 46\r
\n" ); document.write( "\n" ); document.write( " Or, 2(2x - y) = 46\r
\n" ); document.write( "\n" ); document.write( " Or, 2x - y = 46/2 = 23 ......(2)\r
\n" ); document.write( "\n" ); document.write( "Adding equation (1) & (2) we get,\r
\n" ); document.write( "\n" ); document.write( " x + y + 2x - y = 19 +23 = 42\r
\n" ); document.write( "\n" ); document.write( " Or, 3x = 42\r
\n" ); document.write( "\n" ); document.write( " Or, x = 42/3 = 14\r
\n" ); document.write( "\n" ); document.write( "Therefore, I got 14 questions right.\r
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