document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=86142>Question 86142</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 2 times another. If the sum of their reciprocals is 3/20, find the 2 number.\r<BR>\n" );
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document.write( "Any assistance on solving this problem is greatly appreciated. \r<BR>\n" );
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document.write( "Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #62260 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=62260\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One number is 2 times another. If the sum of their reciprocals is 3/20, find the 2 number.<BR>\n" );
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document.write( "Let one of the numbers be \"x\"; The other number is \"2x\".<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "(1/x + 1/(2x)) = 3/20<BR>\n" );
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document.write( "The LCM is 20x<BR>\n" );
document.write( "Multiply thru by the LCD to get:<BR>\n" );
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document.write( "20 + 10 = 3x<BR>\n" );
document.write( "30 = 3x<BR>\n" );
document.write( "x=10<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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