document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1006413>Question 1006413</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this word problem:\r<BR>\n" );
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document.write( "The dimensions of a rectangular monitor screen are such that its length is 3 in more than its width. If the length were doubled and if the width were decreased by 1 in., the area would be increased by 150 in squared. What are the length and width of the screen ?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #622587 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=622587\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length(l) = width (w) + 3<BR>\n" );
document.write( "area = (w + 3) * w<BR>\n" );
document.write( "(2w + 6) * (w - 1) = (w^2 + 3w) + 150<BR>\n" );
document.write( "2w^2 +4w -6 = w^2 +3w +150<BR>\n" );
document.write( "w^2 +w -156 = 0 <BR>\n" );
document.write( "(w+13) * (w - 12) = 0<BR>\n" );
document.write( "w = 12 or -13<BR>\n" );
document.write( "We pick w = 12<BR>\n" );
document.write( "The length = 15 in and width = 12 in of the screen<BR>\n" );
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