document.write( "Question 1006411: \n" ); document.write( "
Algebra.Com's Answer #622557 by ikleyn(52786)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Comments on your proof: \n" ); document.write( " \r\n" ); document.write( "Two column proof.\r\n" ); document.write( "Given: CD is an altitude of ABC, D is the midpoint of BA,\r\n" ); document.write( "Prove: Triangle CDA = Triangle CDB\r\n" ); document.write( "What i think is\r\n" ); document.write( "1. CD is an altitude of ABC - Given\r\n" ); document.write( "2. D is the midpoint of BA. - Given\r\n" ); document.write( "3. Angle ACD = Angle BCD - def of bisected angle <----- The condition says nothing about bisection angle. It is not given\r\n" ); document.write( "4. Angle CD = Angle CD - reflexive property <----- What angle? Three symbols are used to call for an angle.\r\n" ); document.write( "5. Triangle CDA = Triangle CDB - AAS. <----- I'd consider this proof as false.\r\n" ); document.write( "Am i missing something?\r\n" ); document.write( "-------------------------------------------------------------------------\r\n" ); document.write( "Now consider this proof:\r \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Triangles CDA and CDB have the common side CD.\r\n" ); document.write( "They have congruent sides DB and DC (since D is midpoint of BA).\r\n" ); document.write( "The angles CDA and CDB are congruent, since they both are direct angles.\r\n" ); document.write( "Hence, the triangles CDA and CDB are congruent, in accordance with the SAS test for triangles.\r\n" ); document.write( "\r\n" ); document.write( "Yes, it is written not in two column form - sorry.\r\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |