document.write( "Question 1006421: 4 + log(16x) = 24 − 3 log(x)\r
\n" ); document.write( "\n" ); document.write( "i'm not sure how to solve it! \n" ); document.write( "

Algebra.Com's Answer #622543 by Alan3354(69443) $\"\"$ $\"About$

You can put this solution on YOUR website!
4 + log(16x) = 24 - 3 log(x)
\n" ); document.write( "log(16x) = 20 - 3log(x)
\n" ); document.write( "log(16x) = 20 - log(x^3)
\n" ); document.write( "log(16x) + log(x^3) = 20
\n" ); document.write( "log(16x*x^3) = 20
\n" ); document.write( "log(16x^4) = 20
\n" ); document.write( "log(16x^4) = log(10^20)
\n" ); document.write( "16x^4 = 10^20
\n" ); document.write( "2x = 10^5
\n" ); document.write( "x = 50000\r
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