document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1006422>Question 1006422</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ln(x + 4) + ln(x) = ln(x + 40)\r<BR>\n" );
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document.write( "not sure what to do </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #622540 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=622540\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the fact that ln a + ln b = ln ab.\r<BR>\n" );
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document.write( "ln(x+4) + ln x = ln(x^2 + 4x)\r<BR>\n" );
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document.write( "So ln(x^2 + 4x) = ln(x + 40). You should be able to figure it from there. </SPAN>\n" );
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