document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1006367>Question 1006367</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much of a perfume that sells for $15 per ounce should be mixed with a perfume that sells for $35 per ounce to create a 3oz bottle worth $63?\r<BR>\n" );
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document.write( "Amount of $15 perfume= []oz </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #622506 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=622506\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the amount of perfume at $15/oz and y be the amount at 35/oz, then<BR>\n" );
document.write( "x + y = 3<BR>\n" );
document.write( "15x + 35y = 63<BR>\n" );
document.write( "solve first equation for x<BR>\n" );
document.write( "x = 3 - y<BR>\n" );
document.write( "substitute for x in second equation<BR>\n" );
document.write( "15(3 - y) + 35y = 63<BR>\n" );
document.write( "45 - 15y + 35y = 63<BR>\n" );
document.write( "20y = 18<BR>\n" );
document.write( "y = 0.9 oz<BR>\n" );
document.write( "x = 2.1 oz<BR>\n" );
document.write( "2.1 oz of $15/oz perfume<BR>\n" );
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document.write( "check the answer<BR>\n" );
document.write( "15(2.1) + 35(0.9) = 63<BR>\n" );
document.write( "31.5 + 31.5 = 63<BR>\n" );
document.write( "63 = 63<BR>\n" );
document.write( "our answer checks<BR>\n" );
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