document.write( "Question 1006280: 1.given that three numbers form an A.P.their sum is 21,and their product is 231.find these numbers. \n" ); document.write( "
Algebra.Com's Answer #622458 by ikleyn(52794)\"\" \"About 
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1. Given that three numbers form an A.P. Their sum is 21,and their product is 231.find these numbers.
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\n" ); document.write( "\n" ); document.write( "Let  x  be the middle term of this  A.P.\r
\n" ); document.write( "\n" ); document.write( "Then the three terms are  (x-d),  x  and  (x+d).\r
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\n" ); document.write( "\n" ); document.write( "The sum of three is  3x = 21.  Hence,  x = 7.\r
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\n" ); document.write( "\n" ); document.write( "The product of three is  (7-d)*7*(7+d) = 231,     or\r
\n" ); document.write( "\n" ); document.write( "49-d^2 = \"231%2F7\" = 33.\r
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\n" ); document.write( "\n" ); document.write( "Hence,  d^2 = 49 - 33 = 16,  and  d = 4.\r
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\n" ); document.write( "\n" ); document.write( "The three numbers are  7-4 = 3,  7,  and  7+4 = 11.\r
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