document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1006283>Question 1006283</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The average of the measures of angle X, it's complementary angle, and it's supplementary angle is 80 degrees. What is the measure of the complement of angle X?<BR>\n" );
document.write( "A. 30<BR>\n" );
document.write( "B.60<BR>\n" );
document.write( "C.90<BR>\n" );
document.write( "D.120<BR>\n" );
document.write( "E.180 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #622439 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=622439\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> complement of x= 90-x<BR>\n" );
document.write( "supplement of x=180-x<BR>\n" );
document.write( "The sum of x+90-x+180-x=-x+270<BR>\n" );
document.write( "average of those is (-x/3)+90<BR>\n" );
document.write( "That equals 80<BR>\n" );
document.write( "-(x/3)=-10<BR>\n" );
document.write( "x=30\r<BR>\n" );
document.write( "\n" );
document.write( "complement of x=60 ANSWER<BR>\n" );
document.write( "supplement of x=150<BR>\n" );
document.write( "Average of the 3 is (240/3)=80<BR>\n" );
document.write( "B </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );