document.write( "Question 1006237: The solution set in interval notation of the inequality (4/x-1)>(3/x) is:\r
\n" ); document.write( "\n" ); document.write( "A) (-∞, 0)U(0, ∞)
\n" ); document.write( "B) (-3, 0)U(1, ∞)
\n" ); document.write( "C) (-∞, -3)U(0, 1)
\n" ); document.write( "D) (-∞, -3)
\n" ); document.write( "E) (0,1)
\n" ); document.write( "

Algebra.Com's Answer #622411 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Ambiguous inequality, maybe really meant as 4/(x-1)>3/x,\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"4%2F%28x-1%29-3%2Fx%3E0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%284%2F%28x-1%29-3%2Fx%29%28x%28x-1%29%29%3E0%28x%28x-1%29%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"4x-3%28x-1%29%3E0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"4x-3x%2B3%3E0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%2B3%3E0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"highlight%28x%3E-3%29\" which is the interval notation form, (-3, infinity).
\n" ); document.write( "Be aware, a critical value is x at 0. The inequality will be UNDEFINED for x=0.
\n" ); document.write( "Another critical value is x at 1; the inequality is UNDEFINED for x=1.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "You will make better sense of the choices given if your inequality really is exactly as it was shown in your question: \"4%2Fx-1%3E3%2Fx\", and the only critical value would be x at 0 being the undefined value for x in the inequality.
\n" ); document.write( "\"4%2Fx-1-3%2Fx%3E0\"
\n" ); document.write( "\"1%2Fx-1%3E0\"
\n" ); document.write( "\"1-1x%3E0\"
\n" ); document.write( "\"1-x%3E0\".
\n" ); document.write( "Now the critical values of x are 0 and 1.
\n" ); document.write( "The intervals on x to check are (-infinity,0), (0,1), and (1, infinity).\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "--
\n" ); document.write( "One should get all expressions onto one side with 0 on the other side before further simplifying because the denominators may be positive OR negative, affecting the order when performing the multiplication for the order relationship.
\n" ); document.write( "
\n" );