document.write( "Question 1006237: The solution set in interval notation of the inequality (4/x-1)>(3/x) is:\r
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document.write( "A) (-∞, 0)U(0, ∞)
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document.write( "B) (-3, 0)U(1, ∞)
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document.write( "C) (-∞, -3)U(0, 1)
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document.write( "D) (-∞, -3)
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document.write( "E) (0,1) \n" );
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Algebra.Com's Answer #622411 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! Ambiguous inequality, maybe really meant as 4/(x-1)>3/x,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Be aware, a critical value is x at 0. The inequality will be UNDEFINED for x=0. \n" ); document.write( "Another critical value is x at 1; the inequality is UNDEFINED for x=1.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You will make better sense of the choices given if your inequality really is exactly as it was shown in your question: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now the critical values of x are 0 and 1. \n" ); document.write( "The intervals on x to check are (-infinity,0), (0,1), and (1, infinity).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-- \n" ); document.write( "One should get all expressions onto one side with 0 on the other side before further simplifying because the denominators may be positive OR negative, affecting the order when performing the multiplication for the order relationship. \n" ); document.write( " |