document.write( "Question 1006238: If the equation of the circle 4x^2+24x+4y^2-32y=44 can be written as (x-a)^2+(y-b)^2=r^2, then a+b+r=
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document.write( "A) 12
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document.write( "B) 13
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document.write( "C) -1
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document.write( "D) 7
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document.write( "E) 5 \n" );
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Algebra.Com's Answer #622380 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! 4x^2 +24x +4y^2 -32y = 44 \n" ); document.write( "divide both sides of = by 4 \n" ); document.write( "x^2 +6x +y^2 -8y = 11 \n" ); document.write( "complete the square \n" ); document.write( "x^2 +6x +9 +y^2 -8y + 16 = 11 +9 +16 \n" ); document.write( "(x+3)^2 +(y-4)^2 = 36, therefore \n" ); document.write( "a = -3, b = 4, r = 6, then \n" ); document.write( "-3 +4 +6 = 7 \n" ); document.write( "answer is D\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |