document.write( "Question 1006232: Find five numbers that have a mode of 4, a median of 5, a mean of 6 and a range of 7.\r
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Algebra.Com's Answer #622379 by Edwin McCravy(20065)\"\" \"About 
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document.write( "Suppose the 5 numbers are a,b,c,d,e\r\n" );
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document.write( "where a ≤ b ≤ c ≤ d ≤ e \r\n" );
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document.write( "Then: \r\n" );
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document.write( "1. c=5 since it is the median and the median is the middle number when \r\n" );
document.write( "there are an odd number of numbers, and 5 is an odd number of numbers.\r\n" );
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document.write( "2. a=b=4 since the mode is 4. Reasoning: There must be more 4's than \r\n" );
document.write( "anything else.  4 is less than 5, and there must be more than 1 4. \r\n" );
document.write( "But there can only be two numbers less than 5, and that can only be \r\n" );
document.write( "if a=b=4. (We also know that d and e must be different and greater \r\n" );
document.write( "than 5, but we may not need that.)\r\n" );
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document.write( "3. e-a=7 since the range is 7, and since a=4, e-4=7, so e=11\r\n" );
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document.write( "So a=4, b=4, c=5, d=?, e=11\r\n" );
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document.write( "4. (a+b+c+d+e)/5=6 since the mean is 6. Therefore\r\n" );
document.write( "  (4+4+5+d+11)/5=6\r\n" );
document.write( "        (24+d)/5=6\r\n" );
document.write( "            24+d=30\r\n" );
document.write( "               d=6\r\n" );
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document.write( "So the numbers are 4,4,5,6,11   \r\n" );
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document.write( "Edwin
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