document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1006140>Question 1006140</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jack decided to ride his bicycle across the country during his 3-month summer vacation. The<BR>\n" );
document.write( "route he took from Washington, DC to Portland, Oregon, covered a total of 3500 miles. To keep<BR>\n" );
document.write( "his mind occupied during some of the long flat stretches of countryside, he often did algebra<BR>\n" );
document.write( "problems in his head. One day, for example, he determined that his distance from his starting<BR>\n" );
document.write( "point was exactly 80 miles more than twice the distance remaining until the finishing point.<BR>\n" );
document.write( "How far was Jack from the finishing point of his journey when he made that calculation? Start<BR>\n" );
document.write( "your work by defining the unknown quantities in terms of a variable.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #622377 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=622377\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One day, for example, he determined that his distance from his starting<BR>\n" );
document.write( "point was exactly 80 miles more than twice the distance remaining until the finishing point.\r<BR>\n" );
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document.write( "How far was Jack from the finishing point of his journey when he made that calculation?\r<BR>\n" );
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document.write( "x = distance remaining to finish point.<BR>\n" );
document.write( "2x + 80 = distance from start point.\r<BR>\n" );
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document.write( "total distance = x + 2x + 80.<BR>\n" );
document.write( "total distance = 3500<BR>\n" );
document.write( "3500 = x + 2x + 80<BR>\n" );
document.write( "combine like terms to get 3500 = 3x + 80<BR>\n" );
document.write( "subtract 80 from both sides of the equation to get 3420 = 3x<BR>\n" );
document.write( "divide both sides of the equation by 3 to get x = 1140\r<BR>\n" );
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document.write( "he has 1140 miles remaining to get to the finish point.\r<BR>\n" );
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document.write( "he has already traveled 2 * 1140 + 80 = 2360 miles from the start point.\r<BR>\n" );
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document.write( "2360 + 1140 = 3500\r<BR>\n" );
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document.write( "numbers look good.\r<BR>\n" );
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document.write( "2460 is 80 more than twice 1140\r<BR>\n" );
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document.write( "twice 1140 = 2280\r<BR>\n" );
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document.write( "add 80 to get 2360.\r<BR>\n" );
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