document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=86116>Question 86116</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The problem says to \"solve\" the following:\r<BR>\n" );
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document.write( "x/3 - 1/4 = 3x-8/12\r<BR>\n" );
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document.write( "Any assistance provided on this problem is greatly appreciated.  Thank you in advance.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #62232 by </B><A HREF=/tutors/aboutme.mpl?userid=dolly><B>dolly(163)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dolly><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=62232\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I presume the given question to be x/3 - 1/4 = (3x-8)/12\r<BR>\n" );
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document.write( "LCD of the Left side is 12\r<BR>\n" );
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document.write( "==> (4x - 3)/12 = (3x-8)/12\r<BR>\n" );
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document.write( "==> 4x - 3 = 3x - 8   [multiplying by 12 on both sides]\r<BR>\n" );
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document.write( "==> 4x - 3x - 3 = -8\r<BR>\n" );
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document.write( "==> x - 3 = -8\r<BR>\n" );
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document.write( "==> x = -8 + 3\r<BR>\n" );
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document.write( "==> x = -5 is the solution </SPAN>\n" );
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