document.write( "Question 1006176: Physics: I collected some data from Pendulum experiment and I used excel to graph these data in scatter plot and I think the period is proportional to the length. \r
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document.write( "What is the most appropriate linear relation for this graph? e.g. ,
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document.write( "Length(m)|Period(T)Sec|\r
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document.write( "0.30 |1.254 |
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document.write( "0.28 |1.232 |
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document.write( "0.26 |1.204 |
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document.write( "0.24 |1.160 |
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document.write( "0.22 |1.106 |
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document.write( "0.20 |1.044 |
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document.write( "0.18 |1.010 |
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document.write( "0.16 |1.006 |
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document.write( "0.14 |1.004 |
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document.write( "0.12 |0.916 |
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document.write( "0.10 |0.820 |
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Algebra.Com's Answer #622313 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! I plotted your data as points and found the regression line. The regression line does NOT go through the origin. So y = k*x is a bad choice. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Instead I did a power regression and the calculator shows f(x) = 1.92875x^(0.35929)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Notice how if we plug x = 0.12 into f(x) we get f(0.12) = 1.92875*(0.12)^(0.35929) = 0.90039892737524 which is somewhat close to 0.916. It's going to be a bit off because regression curves aren't perfect. Try other x values of the points in your data list.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Side Note: if you still need the regression line, then it is y = 2.01727x + 0.66527 \n" ); document.write( " |