document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1006171>Question 1006171</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The difference between the first number and two times the second number is -54, while the sum of three times the first number plus twice the second is 94. What is the first number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #622311 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=622311\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the numbers x and y.  Then, from the facts we have<BR>\n" );
document.write( "x - 2y = -54 and<BR>\n" );
document.write( "3x + 2y = 94<BR>\n" );
document.write( "Let's add these equations and get<BR>\n" );
document.write( "4x = 40 so that<BR>\n" );
document.write( "x = 10<BR>\n" );
document.write( "We then substitute into either equation (I'll use the 2nd one)<BR>\n" );
document.write( "3(10) + 2y = 94<BR>\n" );
document.write( "30 + 2y = 94<BR>\n" );
document.write( "2y = 64<BR>\n" );
document.write( "y = 32 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );